Re: Problem with Copy Constructor and overloaded assignment operator with templates

From:
 =?iso-8859-1?q?Erik_Wikstr=F6m?= <eriwik@student.chalmers.se>
Newsgroups:
comp.lang.c++
Date:
Tue, 12 Jun 2007 07:16:40 -0700
Message-ID:
<1181657800.356821.172580@i38g2000prf.googlegroups.com>
On 12 Juni, 16:08, saxman <erll...@gmail.com> wrote:

Hi everyone,

I'm writing a class that inherits from std::vector in order to add
some additional functionality. I'm having a compiler problem, however,
when I have a function that returns this class. I've drilled down and
been able to create a very simple example of the problem. Here's my
code:

<code>
#include <vector>
#include <iostream>

using std::vector;
using std::cout;
using std::endl;

template <typename T>
class B : public std::vector<T>
{
public:
  B(){ cout << "In B ctor" << endl; }

  B(B<T> &b) { cout << "In B copy ctor" << endl; }

  B<T>& operator=(const B<T> &b) { cout << "In B assign." << endl;
return *this; }

  ~B(){ cout << "In B destructor" << endl; }

};

B<int> test()
{
  B<int> returnVal;
  return returnVal;

}

int main()
{
  B<int> b;
  b = test();


The problem is that the compiler converts this to a copy-constructor
call like this 'B<int>(test())', however since your copy-constructor
takes a reference as a parameter this can not compile (since a
reference can not bind to the temporary returned by test()). To solve
this simply change the copy-constructor to 'B(const B<T> &b)'. In
general the parameters to copy-constructors should be const.

--
Erik Wikstr=F6m

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