Re: Structure size

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
alt.comp.lang.learn.c-c++,comp.lang.c++
Date:
Fri, 20 Jul 2007 10:27:39 -0400
Message-ID:
<f7qgop$kss$1@news.datemas.de>
LR wrote:

Bruce. wrote:

"Jim Langston" <tazmaster@rocketmail.com> wrote in message
news:YeSni.867$q7.308@newsfe05.lga...

"Bruce." <noone@nowhere.com> wrote in message
news:tlPni.11878$rL1.1904@newssvr19.news.prodigy.net...

"John Harrison" <john_andronicus@hotmail.com> wrote in message
news:vePni.402$Oi4.48@newsfe4-gui.ntli.net...

Since you aren't worried about padding bytes the obvious answer is

typedef struct
 {
     int var1;
     int var2;
     int var3;
     char var4[ 1024 - 3*sizeof(int) ];
 } MYSTRUCT;

Thanks but my example was oversimplified to keep it brief. The
actual structures are much more complex, too complex for a
solution like that. I guess what I was looking for doesn't exist.

But thanks anyway.

Someone already showed you how to use it. Use a union.

#include <iostream>

typedef union
{
   struct {
       int v1;
       int v2;
       int v3;
   } var;
   char unused [1024];
} MyStruct;

int main(void)
{
   MyStruct Foo;

   std::cout << sizeof( Foo ) << "\n";

   Foo.var.v1 = 10;
   Foo.var.v2 = 20;
   Foo.var.v3 = 30;
}

var.v1 will start at position 0.


You forgot var4. I need var4 to be sized automattically to achieve a
structure size of 1024. I need var4 to the size of the remaining
space up to 1024 bytes. In this case it would be:

    struct {
        int v1;
        int v2;
        int v3;
        char v4[1024 - 12];
    } var;

But I want the compiler to figure the 12 automattically.


I'm not sure that I follow what you mean here, but if I do, then I
think that your best bet might be to use either some very complicated
#defines, or perhaps a template. Maybe something like this:

(I'm assuming that as you said in another post, you don't have a
portability problem and you can control your compiler to take care of
packing issues.)

struct x1 {
int a,b,c;
};

struct x2 {
int a; double e,f,g,h,i;
};

template<typename T>
struct Message {
T t;
char v[1024 - sizeof(T)];
};

then, else where you can...

Message<x1> m1;
Message<x2> m2;

there will be the added annoyance of having to reference the
individual members of x1 and x2 by doing something like m1.t.a = 43;
It might be wise to pick a better name for t.

[..]


I am not sure here, but I believe there is no guarantee that the size
of the 'Message<x1>' or 'Message<x2>' is actually going to be 1024
even with the mechanism you give here. I wonder, however, if there
is something in the Standard related to the sizes (and alignments)
that I missed, and it might actually impose certain limitations thus
giving programmers more leeway when it comes to determining type sizes.

V
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