Re: Template with template parameter

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Fri, 20 Jul 2007 13:42:29 -0400
Message-ID:
<f7qs63$ok6$1@news.datemas.de>
Fred Kleinschmidt wrote:

[..]
Actually, what I have is slightly more complex. It's not really
a true copy constructor I need, since there are other parameters.
The constructor has 3 parameters;
   Vct(const Vct&, int, int)
 for various types of Vct<xxx>

I also want constructors passing primitive arrays:
  Vct( const double *, int, int)
  Vct(const float *, int, int)
  ... etc., plus int*, long*, long long*, etc.

And one that I can take a single variable instead of an array:
  Vct( const double, int, int)
  Vct(const float, int, int)
  ... etc., plus int, long, long long, etc.


You can define three different template constructors:

template<class T> class Vct {
    ...
    template<class S> Vct(const Vct<S>&, int, int);
    template<class S> Vct(const S*, int, int);
    template<class S> Vct(S, int, int);
    ...

The problem with the third one is that it's a bit too generic, so
when you use

    Vct<int> vi;
    Vct<double> vd(vi, 1, 2);

it might pick the one with (S, int, int) instead of the one with
(const Vct<S>&, int, int) arguments. To guard against that you
could employ some SFINAE means, like the fact that S in the
(S, int, int) should be convertible to 'double', for example:

    template<class S> Vct(S, int, int, double = S());

in which case it should choke when trying to deduce 'S' as Vct<>&

The same with 'const S*' -- an array of non-const elements may
not be a match. Experiment.

V
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