Re: How can I declare and define a friend template function in a template class?

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Tue, 31 Jul 2007 09:53:35 -0400
Message-ID:
<f8nesu$ok8$1@news.datemas.de>
???? wrote:

First, thank you for your informative tips, I rewrite my code snippet,
here it is:

#include <iostream>
using namespace std;

template<typename T>
class Test;

template<typename T>
Test<T> index(T start, T end, T step);

template<typename T>
class Test {
public:
   friend Test<T> index(T start, T end, T step);
};

template<typename T>
Test<T> index(T start, T end, T step) {
       cout << "This is index is working\n";
       return Test<T>();
}

int main() {

   int start;
   int end;
   int step;

   index(start, end, step);
}

It's the same as you think it is supposed to be, no problem with
compling and linking, but at runtime, a error is raised.


What error do *you* get?

You're passing 'start', 'end', 'step' into the function _without_
_giving them any value_. The lvalue-to-rvalue conversion required
for argument passing causes the program to have *undefined behaviour*.

Try initialising all your variables. Or just call

    index(1, 2, 3);

V
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