Re: explicit copy constructor

Hi, folks,

I am trying to make my copy constructor explicit, but when the
scenario below comes into being, weird things happen.
Here is the code snippet:

#include <iostream>
using namespace std;

class Base {
public:
    Base() {
    }
    Base(const Base& other) {
    }
};

template<typename T>
class Derived: public Base {
public:

    Derived() {
    }

    template<typename U>
    Derived(const Derived<U>& other): Base(*(Base*)&other) {
        cout << "Cast copy constructor\n";
    }

    //here is the trouble maker
    explicit Derived(const Derived& other): Base(*(Base*)&other) {
        cout << "Normal copy constructor\n";
    }
};

int main() {

    Derived<int> d1;

    Derived<int> d2 = d1;

    return 0;
}

Intuitively, I want "Normal copy constructor" printed, but what I saw
is "Cast copy constructor", while I remove "explicit" keyword,
everything is OK, the output is "Normal copy constructor", any
informative tips will receive my big thanks.