Re: emplace() overloads

From:
AlbertoBarbati@libero.it (Alberto Ganesh Barbati)
Newsgroups:
comp.std.c++
Date:
Wed, 21 Nov 2007 21:07:21 GMT
Message-ID:
<Pf01j.175780$%k.314685@twister2.libero.it>
Daphne Pfister ha scritto:

On Nov 20, 1:16 pm, Sylvain Pion <Sylvain.P...@sophia.inria.fr> wrote:

In the current working draft N2461, I read that associative
containers provide:

template <class... Args> pair<iterator, bool> emplace(Args&&... args);
template <class... Args> iterator emplace(const_iterator position,
Args&&... args);

What if I wish to pass a const_iterator as first argument and mean
to use the first overload?

Is this an oversight, or is this a deliberate choice?
What about using a different name for one of the 2 overloads, in order
to prevent the clash?

It seems to me that it would be unlikely that an iterator compatible
with the associative container would be able to construct a value into
the container. In the case* that foo is constructible from a constant
iterator using setname.emplace(setname.begin(),const_iter) should
work.

* I could see using a set for example as a type of tree where
value_type could be constructed with a reference to a parent node
which could be converted from a iterator..

class scope {
public:
  // Using concepts in the next line would be better...
  // just using this pseudo-code for an example.
  template <typename parent_iter> scope(parent_iter const& x) :
parent_(*x) {}
  scope() : parent_(*this) {}
  ...
  scole const& parent_;
};

.
typedef std::unordered_set<scope> scope_set
scope_set scopes;
scope_set::const_iterator root_scope = scopes.emplace().first;
scope_set::const_iterator active_scope = root_scope;
.
if (token == "{") {
  // active_scope = scopes.emplace(active_scope);
  active_scope = scopes.emplace(scope_set.end(),active_scope);
  ...
}


That's a nice example. Please notice that there is another simple way to
rewrite

  // active_scope = scopes.emplace(active_scope);

with "non-hinted" semantic in addition to:

  active_scope = scopes.emplace(scope_set.end(),active_scope);

and that is:

  active_scope = scopes.emplace(scope(active_scope));

if scope has a cheap move constructor and the compiler is reasonably
optimizing, I don't expect to see significant performance differences.

HTH,

Ganesh

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