Re: Member function pointers to member functions with default arguments

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Fri, 25 Jan 2008 07:46:40 +0100
Message-ID:
<13pj1asppbaia91@corp.supernews.com>
* Hamish -> Alf P. Steinbach:

#include <iostream>
using namespace std;

class X {
public:
        void f(int i = 0) { cout << "i = " << i << endl; }
};

template< typename Fn >
void func(Fn f, X &x) {
        (x.*f)();
}

int main() {
        X x;
        func(&X::f, x);
        return 0;
}
// Prints: i = 0.

I was a bit surprised it worked, to be honest. As you said, &X::f
has type void (X::*)(int) so I would have thought Fn would resolve
as void (X::*)(int) causing a compile error on the line (x.*f)();.
Oh well, I'm not complaining.


You should be. :-)

<comeau>
Comeau C/C++ 4.3.9 (Mar 27 2007 17:24:47) for ONLINE_EVALUATION_BETA1
Copyright 1988-2007 Comeau Computing. All rights reserved.
MODE:strict errors C++ C++0x_extensions

"ComeauTest.c", line 11: error: too few arguments in function call
           (x.*f)();
                  ^
           detected during instantiation of
                     "void func(Fn, X &) [with Fn=void (X::*)(int)]" at
line 16

1 error detected in the compilation of "ComeauTest.c".

In strict mode, with -tused, Compile failed
Hit the Back Button to review your code and compile options.
Compiled with C++0x extensions enabled.
</comeau>

<msvc>
vc_project.cpp(11) : error C2198: 'void (__thiscall X::* )(int)' : too
few arguments for call through pointer-to-functio
n
         vc_project.cpp(16) : see reference to function template
instantiation 'void func<void(__thiscall X::* )(int)>(Fn
,X &)' being compiled
         with
         [
             Fn=void (__thiscall X::* )(int)
         ]
</msvc>

<g++>
   <url: http://gcc.gnu.org/bugzilla/show_bug.cgi?id=4205>
</g++>

Cheers, & hth.,

- Alf

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