Re: Operator as non-function
saneman wrote:
But if I try to overload the + operator I get the same error:
template< class A > class BOB;
template< class A >
BOB<A> operator+(typename BOB<A>::difference_type, BOB<A> const& );
template <class A>
class BOB {
private:
typedef BOB<A> iterator;
public:
typedef typename A::difference_type difference_type;
friend iterator operator + <> (difference_type i, const
iterator& it);
// Added overload of + operator
iterator operator + (const difference_type i) const {
return iterator(1);
}
};
When Compiling I get:
error: declaration of ?operator+? as non-function
error: expected ?;? before ?<? token
Where the error refers to:
friend iterator operator + <> (difference_type i, const
iterator& it);
Does that mean that overloading of template operators are impossible?
Take your code to another compiler and see how they react. One of
the most compliant when it comes to templates is Comeau C++. They
have the online trial version. Use it. See what it says. I would
do it myself, but you didn't post the entire code, did you? If I
take what you posted, Comeau compiles it OK.
V
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