Re: partial template specialization for all derived classes

Hi,

I just learned and played around a bit with partial template
specialization, e.g. specializing for all pointers:

#include <iostream>
template<typename T> class MyClass {
  public:
    void someMember() {
        std::cout << "No pointer.\n";
    }
};
template<typename T> class MyClass<T *> {
  public:
    void someMember() {
        std::cout << "Pointer.\n";
    }
};
int main(void) {
    MyClass<int *> pointer1;
    MyClass<char *> pointer2;
    MyClass<int> noPointer;
    pointer1.someMember();
    pointer2.someMember();
    noPointer.someMember();
}

But what I really need is a partial specialization for a specific base
class and all its derived classes, i.e. something like:

#include <iostream>
class Base {};
class Derived: public Base {};
class Any {};
template<typename T> class MyClass {
  public:
    void someMember() {
        std::cout << "Anything else.\n";
    }
};
template<typename T> class MyClass<T: public Base> { // fantasy syntax
  public:
    void someMember() {
        std::cout << "Class Base or any derived class of Base.\n";
    }
};
int main(void) {
    MyClass<Base> base;
    MyClass<Derived> derived;
    MyClass<Any> any;
    base.someMember();
    derived.someMember();
    any.someMember();
}

Is there any way to achieve something like this?