Re: Explicit specialization of inline member functions.
jason.cipriani@gmail.com wrote:
I have a template class declared in a header, with explicit
specialization of certain member functions defined in a source file.
However, I want to define the specialized member functions in the
header, not a separate source file. They can't be defined outside the
class declaration in the header, as that leads to multiple definitions
of the functions in all the source files that include the header.
They can, just add "inline" to the definition, before the return value
type.
However, I don't know the syntax for defining them inside the class
declaration -- and that's my question: is this possible and, if so,
what's the syntax? Right now I have some a test program like this:
=== BEGIN EXAMPLE ===
#include <iostream>
using std::cout;
using std::endl;
template <int N> struct A {
A ();
// <----- I want to put the specialized implementations here.
No, you can't do that. Put them _after_ the class definiton.
};
template<> A<1>::A () { cout << "1!" << endl; }
template<> inline A<1>::A() ...
template<> A<2>::A () { cout << "2!" << endl; }
template<> inline A<2>::A() ...
int main () {
A<1> x;
A<2> y;
return 0;
}
=== END EXAMPLE ===
And what I really want to do is define both of those specialized
constructors in the class declaration instead.
No, not inside. Outside, but "inline">
V
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