Re: How is common_type (N2615) supposed to work?

From:
"Bo Persson" <bop@gmb.dk>
Newsgroups:
comp.lang.c++.moderated
Date:
Mon, 23 Jun 2008 14:47:15 CST
Message-ID:
<6c9vfjF3f4govU1@mid.individual.net>
Greg Herlihy wrote:

On Jun 22, 6:57 pm, "Bo Persson" <b...@gmb.dk> wrote:

From the proposal for new time classes (N2615)


http://www.open-std.org/jtc1/sc22/WG21/docs/papers/2008/n2615.html#co...

I get this common_type traits
template <class ...T> struct common_type;

template <class T>
struct common_type<T>
{
     typedef T type;
};

template <class T, class U>
struct common_type<T, U>
{
private:
     static T&& t();
     static U&& u();
public:
     typedef decltype(true ? t() : u()) type;};

Using gcc 4.3.1, which is the only compiler I have that compiles
it, I tried this simple code:

typedef common_type<int>::type one;
typedef common_type<int, int>::type two;

The compiler seems to agree with me that 'one' is a typedef for
'int' while 'two' is a typedef for'int&&'. Why is that?


Because finding a single type that a set of types all convert to -
is easy done when there is only one type in the set. Along the same
lines, finding a a common type when all the types in the set are the
same type - is not any harder. Both of the these cases could be
called "trivial".


I can see that, but the not so trivial (to me, at least) part is why a
single int gives 'int', while two ints give 'int&&'. Why the
difference?

Bo Persson

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