Re: ambiguous call to overloaded template function

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Mon, 30 Jun 2008 09:40:19 +0200
Message-ID:
<HoqdnfxDZJJ6EPXVnZ2dnUVZ_jqdnZ2d@posted.comnet>
* Ruki:

I want to overload function to swap two others types, for example,
type<T>, T* and so on,
but I can't compile the following code at VC 6.0.

The compiler says :
error C2667: 'swap' : none of 2 overload have a best conversion
error C2668: 'swap' : ambiguous call to overloaded function
-------------------------------------------------------------------------------------------------------------
template < typename T >
void swap(T &lhs, T &rhs)
{
    // do some thing
}

template < typename T >
void swap(T *lhs, T *rhs)
{
    // do some thing
}

template < typename T >
struct type{};

template < typename T >
void swap(type<T> &lhs, type<T> &rhs)
{
    // do some thing
}
int main()
{
    int *p1,*p2;
    type<int> t1, t2;
    swap(t1, t2);
    swap(p1, p2);

Compiles fine with two modern compilers.

Don't use VC6, it's old.

Don't use the name 'swap', it's used by the standard library.

Don't try to be too subtle, like relying on subtleties of overload resolution.

Why don't you just use std::swap instead of defining your own?

Cheers, & hth.,

- Alf

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