Re: Why koenig lookup?

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 12 Aug 2008 02:03:48 -0700 (PDT)
Message-ID:
<6b38f15d-45a2-4c51-8ba3-15b1eb4f5ad4@m44g2000hsc.googlegroups.com>
On Aug 11, 8:10 pm, Diego Martins <jose.di...@gmail.com> wrote:

On Aug 11, 8:04 am, "Alf P. Steinbach" <al...@start.no> wrote:

* Alf P. Steinbach:

I now think I/we? have been blaming the wrong guy, ADL.

The whole thing about global namespace operator<< overload
problem, being just a case of name hiding.


what is the best solution for the operator<< example presented
above? I runned into the same problem once and I putted my
operator<< inside std:: as a quick non-std solution :-(


You mean overloading operator<< for something like
std::vector<double>? The best solution is not to do it, at all.
What happens if a collegue is also using std::vector<double>,
and also wants to overload<< for it?

What you want is a type with known semantics, or rather, with a
known standard display format. In mathematics, for example,
you'd almost certainly have a Vector class, with various
additional operators not supported by std::vector<double>.
Unless it was a Polynome class. In exceptional cases where you
really do have a raw std::vector, you can create a small
decorator class which does the trick:

    template< typename T >
    class AsVector // mathematical vector...
    {
    public:
        explicit AsVector( std::vector< T > const& v )
            : myV( v )
        {
        }
        friend std::ostream&
                        operator<<( std::ostream& dest,
                                    AsVector const& source ) ;

    private:
        std::vector< T > const&
                        myV ;
    } ;

    template< typename T >
    inline AsVector< T >
    asVector( std::vector< T > const& v )
    {
        return AsVector< T >( v ) ;
    }

AsPolynome would be similar, except that the code for the
operator<< would be very different.

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