Re: Making a smart pointer which works with incomplete types

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 7 Sep 2008 09:46:15 -0700 (PDT)
Message-ID:
<79025c02-e8fb-4ae7-abb7-0a8f33ef859a@59g2000hsb.googlegroups.com>
On Sep 7, 4:11 pm, "Alf P. Steinbach" <al...@start.no> wrote:

* Kai-Uwe Bux:

Alf P. Steinbach wrote:

* Kai-Uwe Bux:

Alf P. Steinbach wrote:

* Juha Nieminen:

  Then it occurred to me: Is there any reason this pointer cannot b=

e

static? Like this:

//-----------------------------------------------------------------=

-

template<typename Data_t>
class SmartPointer
{
...
    static void(*deleterFunc)(Data_t*);
...
 public:
    SmartPointer(Data_t* d): data(d)
    {
        deleterFunc = &deleter;
    }
...
};

template<typename Data_t>
void(*SmartPointer<Data_t>::deleterFunc)(Data_t*) = 0;
//-----------------------------------------------------------------=

-

  This way the pointer to the deleter will be stored in the program
  only
once, and most importantly it will not increment the size of the sm=

art

pointer.

  This feels so glaringly obvious to me now that I really wonder wh=

y

this wasn't suggested to me to begin with. Is there some error here=

 I'm

missing?

Yeah. Successive smart pointer instantiations can change the common
deleter func pointer.

[snip]

How?

Sorry, I reacted to the static pointer. As I wrote use a template
parameter instead. The only valid reason for having a pointer to that
function is to change the pointer, and that's apparently done in the
constructor body,


Really? Then a smart pointer working with incomplete types
(in the sense above) either does not qualify as a valid
reason or there must be a way without that (static) pointer.
Which is it? and if it is the second, which way of making a
smart pointer work with incomplete types do you have in
mind?


Consider the following:

   template< typename T >
   void destroy( T* );

   template< typename T >
   class SmartPointer
   {
   ...
   public:
       ~SmartPointer() { if( ... ) { destroy( myReferent ); } }
   };

It achieves the same as the original code without any static pointer.


No. With the original code, you can delete the pointer in a
context where the type is incomplete. with your code, you
can't.

For more flexibility (in the direction that a static pointer
could add flexibility) make the deleter a template parameter.


Which would require the type to be complete when you
instantiation the template.

--
James Kanze (GABI Software) email:james.kanze@gmail.com
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