Re: Recursive templates

From:
Barry <dhb2000@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 4 Nov 2008 16:35:46 -0800 (PST)
Message-ID:
<245e7f9f-53b8-4b1f-80e7-431939c03120@b31g2000prf.googlegroups.com>
On 11=D4 4=C8=D5, =CF =CE=E711=CA=B116=B7=D6, andreyvul <andrey....@gma=
il.com> wrote:

On Nov 4, 10:12 am, Barry <dhb2...@gmail.com> wrote:

On 11=D4 4=C8=D5, =CF =CE=E711=CA=B104=B7=D6, andreyvul <andrey....=

@gmail.com> wrote:

I have a template function like this:
std::vector<std::pair<Square<T>, Triangle<T> > > *
recarrow(T a, T b, int n) {
/* ... */

}

template <class T>
struct Square {
        /* ... */};

template <class T>
struct Triangle {
        /* ... */

};

Now, g++ has problems recursively creating the std::vector from
Square<T>.
Are recursive templates part of C++98 (or even C++0x) or is g++ just
non-compliant?


You need to forward declaring the two template class before you used
them in the function definition(or even declaration) of "recarrow"

template <class T>
struct Square;

template <class T>
struct Triangle;

And don't foget "template <class T>" for recarrow.


So why must I forward-declare the definition instead of the body?
Is this similar to C's
typedef struct A {
     B b;} A;

typedef struct B {
    A a;} B;

?

The actual code was:
template <class T> struct Square {}
template <class T> struct Triangle {}
std::vector<std::pair<Square<T>, Triangle<T> > > *
recarrow(T a, T b, int n) {}

Why must the template class be forward-declared still?


You don't have to if you define "Square" and "Triangle" before the
template
function "recarrow". And don't forget "template <class T>" before
recarrow again.

But from the title of your post -- "Recursive", I wildly guesses that
you
want things that way.

--
Best Regards
Barry

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