Re: template class constructor shall be called from the initializer

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Wed, 19 Nov 2008 16:10:40 CST
Message-ID:
<ab7579c5-f39c-417e-9057-880123475126@c1g2000yqg.googlegroups.com>
On 19 Nov., 21:24, annamalai <annamalai.gurus...@gmail.com> wrote:

        list of the inheriting, non-template class constructor
On Nov 17, 1:18 am, Daniel Kr?gler <daniel.krueg...@googlemail.com>
wrote:

In short my reading of the standard is that the OP's
usage of the shortened naming of the injected-class-name
'A' should be well-formed and well-defined (ignoring
some typos in the example and the fact that 'sometype'
wasn't declared anywhere).


As pointed out by Matthias Berndt, what happens when the class derives
from both A<int> and A<float>, as follows:

$ cat base.cc
template <typename T>
struct A {
   A() {}
   T t;

};

struct B : A<int>, A<float> {
   B(): A() {} // A is A<int> or A<float>?

};

int main() { B obj; }
$

Any thoughts on this situation?


The standard already handles this situation, see
N2798, [temp.local]/4:

"A lookup that finds an injected-class-name (10.2) can
result in an ambiguity in certain cases (for example,
if it is found in more than one base class). If all of
the injected-class-names that are found refer to
specializations of the same class template, and if the
name is followed by a template-argument-list, the
reference refers to the class template itself and not a
specialization thereof, and is not ambiguous. [ Example:
template <class T> struct Base { };
template <class T> struct Derived: Base<int>, Base<char> {
  typename Derived::Base b; // error: ambiguous
  typename Derived::Base<double> d; // OK
};
?end example]"

Thus your example should cause an ambiguouity.

Greetings from Bremen,

Daniel Kr?gler

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