Re: Explicit template initialization linkage problems (VS2005)
"(2b|!2b)==?" <void-star@ursa-major.com> wrote in message
news:QfqdnZkKC8SKl_7UnZ2dnUVZ8vqdnZ2d@bt.com
I am getting linkage errors building a class with method templates.
The class looks like this:
class A
{
public:
A();
~A();
template <typename T>
long foo(T& val, string& key) const ;
private:
class B { /* Heavy object that manages internals of A */ };
};
The implemntation of template function foo<T>, uses class A::B -
Class B is 'heavy' and therefore, I do not want to include the
implemntation of A::B in A.h
Consequently, I cannot inline foo's implementation in A.h
I don't see how this follows from the previous paragraph. foo would only
need to see a definition of B, which you seem to already have in A.h
anyway. Actual implementation of A::B's methods can happily go into a
..cpp file.
Also, since B doesn't appear to be a template, the implementation of foo
likely consists of two parts, one that depends on T and one that doesn't
(and uses B). Perhaps it could be broken into two functions, one
templated and one not, where the former calls the latter?
A.cpp
=====
A::B(){}
Surely you mean A::B::B() {}
--
With best wishes,
Igor Tandetnik
With sufficient thrust, pigs fly just fine. However, this is not
necessarily a good idea. It is hard to be sure where they are going to
land, and it could be dangerous sitting under them as they fly
overhead. -- RFC 1925