Re: Inheriting type names from templatized bases - legal or not ?

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Thu, 05 Mar 2009 11:02:01 +0100
Message-ID:
<goo7uu$khs$1@news.motzarella.org>
* Jean-Louis Leroy:

Is the following code legal ?


Nope.

template<typename T>
struct base
{
  typedef T type;
};

template<typename T>
struct derived : base<T>
{
  derived(type x);
};

g++ 3.3.4 and Visual Studio 2005 accept it. OTOH I don't see how they
recognize "type" as a type name.


Comeau C/C++ 4.3.10.1 (Oct 6 2008 11:28:09) for ONLINE_EVALUATION_BETA2
Copyright 1988-2008 Comeau Computing. All rights reserved.
MODE:strict errors C++ C++0x_extensions

"ComeauTest.c", line 10: error: identifier "type" is undefined
     derived(type x);
             ^

1 error detected in the compilation of "ComeauTest.c".

I would expect "typename
base<T>::type" to be required in "derived<T>".


Yep.

Except for one detail in the context of usage as a base class when deriving.

As I recall in that context instead of being required, 'typename' is forbidden.

Cheers & hth.,

- Alf

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