Re: std::norm defect?

From:
SG <s.gesemann@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 8 Mar 2009 07:46:55 -0700 (PDT)
Message-ID:
<ca5ef38f-2ad7-4d6e-82e8-a66ca3d89970@41g2000yqf.googlegroups.com>
On 4 Mrz., 08:49, highegg <high...@gmail.com> wrote:

Just an update: I've sent the GCC developers the following patch to
the "complex" header:

Index: libstdc++-v3/include/std/complex
=========================

==========================
==================

--- libstdc++-v3/include/std/complex (revision 144596)
+++ libstdc++-v3/include/std/complex (working copy)
@@ -649,8 +649,13 @@ _GLIBCXX_BEGIN_NAMESPACE(std)
       template<typename _Tp>
         static inline _Tp _S_do_it(const complex<_Tp>& __z)
         {
- _Tp __res = std::abs(__z);
- return __res * __res;
+ const _Tp __x = abs(__z.real());
+ const _Tp __y = abs(__z.imag());
+ const _Tp __s = std::max(__x, __y);
+ const _Tp __r = std::min(__x, __y);
+ if (__s == _Tp())
+ return __s;
+ return __s * (__s + __r * (__r / __s));
         }
     };


This is me just nit-picking: You used qualified names for max and min.
In generic user code this is discouraged because it prevents ADL. But
ADL is all you have left if you want min/max calls to resolve to your
own function templates:

  namespace mymath
  {
    template<typename Integer> class rational;

    template<typename Integer>
    rational<Integer> min(rational<Integer> const& a,
                          rational<Integer> const& b);
  }

This is the only possibility because you can't partially specialize
std::min and std::max. Also, overloading them in the namespace "std"
is illegal as far as the C++ standard is concerned (it usually works,
though).

So, in generic user code (some other namespace than std) you would
write:

    template<typename T>
    T do_it(const complex<_Tp>& __z)
    {
       using std::min;
       using std::max;
       ...
       const T s = max(x,y); // ADL still works
    }

If I remember correctly this is covered in "Effective C++" by Scott
Meyers.

Cheers!
SG

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