Re: Template partial specialization

From:
SG <s.gesemann@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 17 Mar 2009 02:39:27 -0700 (PDT)
Message-ID:
<053163fc-1290-4ac1-814f-5813565c8cbb@v19g2000yqn.googlegroups.com>
On 17 Mrz., 10:02, Misiu <misi...@onet.eu> wrote:

template <typename T>
struct test
{ static const bool value = false; };

template <typename T>
// For vector itself is OK
struct test<std::vector<T> >

//but not for its iterator: expected a type, got =91std::vector::iterator=

'

struct test<std::vector<T>::iterator >
{ static const bool value = true; };


Think about it. How can the compiler check whether your type
parameter matches std::vector<T>::iterator for some unknown T? In
case of std::vector this may seem trivial but std::vector is an
ordinary class template which could have looked like this:

  template <typename T>
  class vector { typedef int iterator; };

If you then explicitly instantiate a class via

  template test<int>;

what kind of class should be instantiated? In this case
int==vector<T>::iterator for ALL possible types T. The problem here
is deducing T or in other words inverting the meta function that maps
type T -> type std::vector<T>::iterator. Also, this wouldn't be
really a specialization since std::vector<T>::iterator could be
basically anything you want it to be via specialization of
std::vector.

Cheers!
SG

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