Re: compilation error with function template parameter

From:
Victor Bazarov <v.bazarov@comcast.invalid>
Newsgroups:
comp.lang.c++
Date:
Fri, 27 Aug 2010 08:24:31 -0400
Message-ID:
<i58aq0$8os$1@news.eternal-september.org>
On 8/27/2010 8:09 AM, subramanian100in@yahoo.com, India wrote:

The following quesion is NOT a HOMEWORK problem.

Consider the following x.cpp:

#include<cstdlib>
#include<iostream>

using namespace std;

template<class T>
inline void fn(void (T::*memfnPtr)())
{
         return;
}

class Test
{
public:
     void member();
     void member() const;
};

inline void Test::member(void)
{
         cout<< "Test::member() called"<< endl;

         return;
}

inline void Test::member(void) const
{
         cout<< "Test::member() const called"<< endl;

         return;
}

int main()
{
         fn(&Test::member);

         return EXIT_SUCCESS;
}

When I compile this program with g++3.4.3 as
g++ -std=c++98 -pedantic -Wall -Wextra x.cpp

I get the following compilation error:
x.cpp: In function `int main()':
x.cpp:35: error: no matching function for call to `fn(<unknown type>)'

Why do I get this compilation error ? Kindly explan. Please help to
fix this error. I do not get the compilation error, if I have the
function template 'fn()' as follows:
template<class T>
inline void fn(void (T::*memfnPtr)() const)
{
         return;
}

Note that in the above modified version of 'fn()', I have added
'const' to the parameter. Why don't I get the compilation error
for this version but I do get for the earlier version ?


Most likely a bug in the compiler. Comeau C++ accepts the code without
a hiccup. So does Visual C++ 2008 (it points out that the argument of
the template 'fn' is unused, but it's a warning).

V
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