Re: Accessing a protected member in a derived class

Hi NG,

The following example does not compile using g++. The compiler says
"error: ???iMyVal??? was not declared in this scope" in Method MyFunction
of the derived class:

template<typename T>
class MyBase
{
protected:
   int iMyVal;
};

template<typename T>
class MyDerived : public MyBase<T>
{
   void MyFunction()
   {
     // this->iMyVal = 10;
     iMyVal = 10;
   }
};

int main()
{
   MyDerived<int> derived;
   return 0;
}

Using the line with the this-> works fine. After removing the template
stuff the code compiles also fine without this->: