Compile-time introspection of free-floating functions, does this work?

From:
Juha Nieminen <nospam@thanks.invalid>
Newsgroups:
comp.lang.c++
Date:
13 Feb 2012 19:11:09 GMT
Message-ID:
<4f39604d$0$4386$7b1e8fa0@news.nbl.fi>
  I think I might have come up with a way to detect at runtime if a
free-floating function has been defined or not, and avoid referencing
it if it isn't. More concretely, in a project of mine I need to know
if std::strtold exists in <cstdlib> or not, and call it only if it does
(and if it doesn't, fall back to calling std::strtod).

  What's the jury's opinion of this? Standard, non-standard, ill-formed,
suspicious? Any suggestions to make it better?

//---------------------------------------------------------------------
#include <iostream>
#include <cstdlib>

namespace std
{
    template<typename T1, typename T2>
    char strtold(T1, T2);
}

namespace
{
    const bool hasStrtold =
        (sizeof(std::strtold("0", (char**)0)) > 1);

    template<bool> struct Func;

    template<> struct Func<false>
    {
        static void func() { std::cout << "No strtold().\n"; }
    };

    template<> struct Func<true>
    {
        static void func()
        {
            std::cout << "Has strtold(). Test: "
                      << std::strtold("12.3", (char**)0) << "\n";
        }
    };

    void func()
    {
        Func<hasStrtold>::func();
    }
}

int main()
{
    func();
}
//---------------------------------------------------------------------

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