Re: how to make a common template class that wraps alternate template classes without having to write all of the interfaces?

From:
Victor Bazarov <v.bazarov@comcast.invalid>
Newsgroups:
comp.lang.c++
Date:
Tue, 24 Jul 2012 08:16:14 -0400
Message-ID:
<jum3mf$md4$1@dont-email.me>
On 7/24/2012 3:33 AM, Juha Nieminen wrote:

tonyk <tkirke@gmail.com> wrote:

Hi,
I'm wondering what is the most elegant way to do the following
Assume there are 2 or more different vendor fixed-point template classes
such as
template <int T> v1_int<T>; // always signed
and

template <int T, bool S> v2_int<T,S>; // S for signed/unsigned
(not different template params)

Now I'd like to create a template class
template <int T> V_int<T>;
such that with a #define or another technique have V_int represent either
v1_int<T> or v2_int<T,true> without having to re-write all of the member
interfaces, overloads, etc

is that possible? Any advice appreciated


If you are using C++11, you can use a template alias for that exact
purpose. It would be something like this:

#ifdef SOMETHING
template<int T> using V_int = v1_int<T>;
#else
template<int T> using V_int = v2_int<T, true>;
#endif

The above doesn't work in C++98, and I'm not sure now what would be the
easiest alternative (if there is one in the first place).


There was/is no direct alternative to template aliases. One could wrap
the other template definition, but it will require another level of
indirection:

#ifdef SOMETHING
   template<int T> struct V_int { typedef v1_int<T> type; }
#else
   template<int T> struct V_int { typedef v2_int<T,true> type; }
#endif

and use V_int<T>::type instead. The "::type" is the indirection.

V
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