Re: How dynamic_cast works internally?

From:
=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?= <Erik-wikstrom@telia.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 23 Oct 2007 07:56:06 GMT
Message-ID:
<qOhTi.11995$ZA.7879@newsb.telia.net>
On 2007-10-23 08:55, Bo Yang wrote:

Erik Wikstr??m

On 2007-10-22 15:19, Bo Yang wrote:

Greg Herlihy :

On Oct 22, 2:20 am, Lance Diduck <lancedid...@nyc.rr.com> wrote:

On Oct 22, 4:51 am, Bo Yang <struggl...@gmail.com> wrote:> Hi,

  I can understand static_cast, reinterpret_cast and const_cast, they
all work at compile time. But I can figure out how the C++'s dynamic-
cast works? Could you please explain how for me?
Thanks in advance!
Regards!
Bo

Consider this case:
class A{virtual ~A(){};};
class B:public A{};
A*a=new B;
B*b =dynamic_cast<B*>(a);. .
B* Dynamic_Cast(A*a ){
    if(*((a->vptr)+1)()==B_RTTI())
       return a;
    return 0;

}

This implementation might work for typeid - because typeid has to
confirm only that type of the object being tested - matches the
specified type exactly.

A dynamic_cast operator however has to perform a much more complicated
test: whether an object (of unknown thype) is related to another type.
And to make do with a lot less information about the classes involved
than existed in the example above. For example:

   struct A
   {
      virtual ~A() {}
   };

   bool TestA(void *p)
   {
      assert( p != NULL);
      return dynamic_cast<A*>(p) != NULL;
   }

Note that no derived classes of A (if any exist) are visible when this
source file is compiled. So no matter how many large or complex this
program's class hierarchy might be, dynamic_cast<> has only the "A"
class declaration with which to work here.

So how is dynamic_cast<> supposed to figure out whether p points to a
type that is somehow related to A? Well, given these constraints,
there is only one way to solve this problem. dynamic_cast must search
p's class hierarchy (essentially, discovering its layout as it goes
along) and to continue the search until either a A class is located
with the hierarchy - or there are no other classes left in the
hierarchy that need to be checked.

So, how C++ go along the classes hierarchy at runtime? RTTI? Is RTTI a
standard of C++? I think RTTI is not a standard part of C++!


RTTI is part of the C++ standard, do not confuse it with reflection
though. One way to accomplish this (though I do not think that is how it
is done) would be to add a second pointer (in addition to the vtable)
which points to a type object looking something like this:

class Type
{
  char name[];
  Type* super[];
  Type* derived[];
};

That way typeid could (conceptually) be implemented something like this:

template<typename T>
type_info typeid(T t)
{
  return type_info(t->typePtr->name)
}

And using some simple tree walking algorithms you can find out if a type
is in the same type-hierarchy as another.


So, C++ type conversion will be time-consuming and space-consuming,
right? And maybe that is why C++ program is much more big than C's?


As I said, that was only a conceptual example, I do not know how they
really do it in a compiler. But you should notice that all but
dynamic_cast can be done at compile-time without any extra run-time
information, so to claim that C++ casts are more costly than C casts are
not really true. On the other hand, added type-safety obviously does not
come for free, so some extra overhead is inevitable.

--
Erik Wikstr??m

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