Re: About list::sort() in STL

From:
red floyd <no.spam@here.dude>
Newsgroups:
comp.lang.c++
Date:
Wed, 24 Oct 2007 11:42:34 -0700
Message-ID:
<TmMTi.7328$Pv2.1272@newssvr23.news.prodigy.net>
gjin@mail.utexas.edu wrote:

On Oct 24, 12:35 pm, red floyd <no.s...@here.dude> wrote:

g...@mail.utexas.edu wrote:

Hi there,
    I met a problem, which I could not solve. I used it as the
following:
list<long> L
for (long i=1;i<=479250; i++)
L.push_back(i);
L.size(); // this gives 479250;
L.sort();
L.size(); // Here it gives 20498?
Why the elements in the list are removed??? I could not understand it
Really appreciate your help!

Doesn't happen in g++ 3.4.4. What is your platform? Please provide a
minimal *COMPILABLE* (emphasis on compilable) example that exhibits the
behavior in question.

Thank you.- Hide quoted text -

- Show quoted text -


I use Visual C++ 6.0. Here is a simple example I test, which does not
work.


VC6 is known for buggy implementations of templates. This looks to be
an error in the compiler or library (Sorry PJ and Pete!). That is,
assuming that you ran the code below (after fixing the typo) and got the
output you claimed.

The other issue is that it could be a data type error. Note that
479250%65536 is 20498.

Are you sure that's the actual code you tested, and that you're not
assigning to any variables in between?

#include <iostream>
#includer<list>

using namespace std;

int main()
{

   list<long> L;

   for (long i=1;i<=479250; i++)
      L.push_back(i);

    cout<< L.size()<<endl; // give 479250

    L.sort();

    cout<< L.size() << endl; // give 20498;???

    return 0;
}

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