Re: Possible to require overloading of a non-pure method?

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Fri, 25 Apr 2008 11:58:14 -0400
Message-ID:
<fusv2p$868$1@news.datemas.de>
Thomas J. Gritzan wrote:

[rob desbois] schrieb:

On Apr 25, 12:46 pm, Pete Becker <p...@versatilecoding.com> wrote:

On 2008-04-25 06:40:20 -0400, "[rob desbois]"
<rob.desb...@gmail.com> said:

Hi all, I have a set of classes which implement the virtual
constructor idiom.
I had a slicing problem which resulted when I forgot to override
the clone() function in a derived class.
Is there something (other than documentation) that I can do to
prevent this from happening again?

Unit testing and code reviews.


Allow me to clarify. I meant is there any language construct which
can enforce this requirement.

A unit test wouldn't have helped -- I'd have had to remember to write
a unit test for the new class's clone() method ensuring that the
returned pointer is castable to a pointer to the new derived type. If
I'd have remembered that I'd have remembered to code the clone method
anyway.


"Design by Contract".

Something like (untestet):

class Base
{
public:
   Base* clone() const
   {
      Base* p = doClone();
      assert(typeid(*p) == typeid(*this));
      return p;
   }

private:
   Base* doClone() const
   {
      return new Base(*this);
   }
}

    ;

First off, no virtual functions here, did you mean to make 'doClone'
virtual? And second, he needed the compile-time solution, AIUI.

And how does 'typeid' trick work? Does 'typeid' return the dynamic
type of '*this'? So, if you derive from 'Base', what then? How
does the splitting of the function in two help _forcing_ the derived
class provide the override?

V
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