Re: how to generate unique namespaces

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 18 Sep 2008 01:55:41 -0700 (PDT)
Message-ID:
<da965be2-be77-434c-bd79-78df6fdb6f8e@x35g2000hsb.googlegroups.com>
On Sep 18, 5:04 am, Ian Collins <ian-n...@hotmail.com> wrote:

er wrote:

here's why i'm trying to do:

header1.hpp
namespace{ struct A{};}
struct B1{ A a; };

header2.hpp
namespace{ struct A{};}
struct B2{ A a; };

*.cpp
#include <libs/testing_namespace/header1.hpp>
#include <libs/testing_namespace/header2.hpp>

header2.hpp|5|error: redefinition of ?struct<unnamed>::A?|

i should expect that because the translation unit includes
both header1 and header 2. so then how can i automatically
generate unique namespaces, one for each of header1 and
header2?


You can't.


For some definition of "unique". Something like:

    namespace header1_private { /* ... */ }

is sufficient for a lot of cases. Or for the really paranoid:
corporate_name_division_name_departement_name_header1.

And since nobody has mentionned it: you almost never want an
anonymous namespace in a header. In his case, for example, if
header1.hpp is included in more than one translation unit, he
has undefined behavior, because of a violation of the one
definition rule for B1.

If you must, use a code generator.


Like you do for the include guards?

If you automatically generate unique namespaces, how do you
use them?


As you said, with a code generator:-). As long as everything is
generated by the same code generator, everything is hunky dory.
(This works for include guards because except for the #ifdef and
immediately following #define, you never use the symbol. And
those are automatically inserted by the "code generator" when
you create the file.)

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