Re: std::string class instance are immutable or not??

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Fri, 06 Feb 2009 22:57:25 +0100
Message-ID:
<gmibll$bvv$1@news.motzarella.org>
* Alf P. Steinbach:

* SG:

On 6 Feb., 17:54, "Alf P. Steinbach" <al...@start.no> wrote:

* SG:

Assembling a string that way is very costly which is why in C# and in
Java you typically have a StringBuilder class which is like a string
but mutable.

I'm sorry but that is incorrect.


In Java it is the case (just tested on Sun's JVM/Compiler 1.6.0_10) by
wich I mean


Oops, I forgot to comment on that.

Yes, it seems '+=' has inefficient implementations in Java and C#, but the
inefficient implementations are not inefficient because '+=' is costly for
immutable strings, as you wrote; on the contrary, '+=', as opposed to infix '+',
allows for maximum efficiency.

The Java and C# '+=' ops are just inefficient silly implementations.

For a faster implementation of '+=' for immutable strings you might look at (old
code and never quite finished) <url: http://alfsstringvalue.sourceforge.net/>;
of course, when I wrote that page & code, pointing to Java and C# for
efficiency, I didn't know that Java and C# are so inefficient! :-)

And by the way, in the test programs I now see that the C++ version had just
half the number of operations, which made C++ look very very efficient in
comparision; doubling the number of operations to the same as for Java and C#
makes it just somewhat more efficient than C#:

<results language="C++">
C:\temp> a
Infix '+' : 0.3910
concat : 0.0000
'+=' operator: 0.0000

C:\temp> a
Infix '+' : 0.3290
concat : 0.0160
'+=' operator: 0.0000

C:\temp> a
Infix '+' : 0.3280
concat : 0.0000
'+=' operator: 0.0000

C:\temp>
</results>

Cheers & hth.,

- Alf

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