Re: Type traits and accessibility

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Wed, 14 Apr 2010 12:17:14 CST
Message-ID:
<5950cca0-26f1-465f-916b-92a2a4300715@b23g2000yqn.googlegroups.com>
On 14 Apr., 13:18, Mathias Gaunard <loufo...@gmail.com> wrote:

On 13 avr, 22:57, Daniel Kr?gler <daniel.krueg...@googlemail.com>
wrote:

std::is_constructible
needs compiler-support


Not necessarily.
You could use SFINAE to check whether the expressions that defines
is_contructible's value are well-formed.


Nope, SFINAE is *not* access-tolerant. Just try

template<class T>
struct HasStaticFoo {
  typedef char No;
  typedef char(&Yes)[2];
  template<class U, class = decltype(U::foo())>
  static Yes test(void*);
  template<class>
  static No test(...);
  static const bool value = sizeof(test<T>(0)) == sizeof(Yes);
};

struct S {
  static void foo();
};

struct D {};

class X {
  static void foo();
};

static_assert(HasStaticFoo<S>::value, "Ouch");
static_assert(!HasStaticFoo<D>::value, "Ouch");
static_assert(!HasStaticFoo<X>::value, "Ouch");

int main() {}

with a recent C++0x capable compiler and you will notice
that the error for X is *not* related to a violation of static_assert.

is_constructible and is_convertible are traits that *require*
compiler support, because they were intended to cope with
access restrictions. I haven't tested recent implementations
but I would expect that most of them still behave like normal
SFINAE-based realizations, which - strictly speaking - are
non-conforming, but the easiest to do for the moment.

HTH & Greetings from Bremen,

Daniel Kr?gler

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