Re: strange threading context

From:
"Chris M. Thomasson" <no@spam.invalid>
Newsgroups:
comp.lang.c++
Date:
Sat, 16 Aug 2008 21:00:28 -0700
Message-ID:
<ojNpk.5334$dB6.3677@newsfe01.iad>
"A.Gallus" <uh5d@rz.uni-karlsruhe.de> wrote in message
news:g87gvg$u73$1@news2.rz.uni-karlsruhe.de...

This is my problem:

I have two classes A and B:

class A
{
   void methodA();
}

class B
{

   void methodB();

   struct S
   {
       int Size;
   };

   S & getMyStruct();

   S MyStruct;

}

methodA and methodB get executed in two different threads concurrently.
They both access the variable Size in the structure MyStruct of type S.
methodA gets a reference to this struct by calling getMyStruct which
returns a reference
to it.
Here comes the strange part:
if methodB alters the value of Size from 0 to 1, this change doesn't get
reflected in methodA - methodA
still reads a 0. The access to the struct MyStruct is sychronized by a
mutex.


Well, let me try to read your mind and see if I can make a better model in
the form of fully compliable code:

code listing 1 with a race-condition!
______________________________________________________________________
#include <cstdio>
#include <pthread.h>

class mutex_guard {
  pthread_mutex_t* const m_mutex;

public:
  mutex_guard(pthread_mutex_t* const mutex)
   : m_mutex(mutex) {
    pthread_mutex_lock(m_mutex);
  }

  ~mutex_guard() {
    pthread_mutex_unlock(m_mutex);
  }
};

class A {
public:
  void methodA();
};

class B {
  friend class A;

  struct S {
    int Size;
    S() : Size() {}
  };

  S MyStruct;

  S& getMyStruct() {
    return MyStruct;
  }

  static pthread_mutex_t g_mutex;

public:
  void methodB();
};

pthread_mutex_t B::g_mutex = PTHREAD_MUTEX_INITIALIZER;

static B g_global_instance_of_B;
static A g_global_instance_of_A;

void A::methodA() {
  mutex_guard lock(&B::g_mutex);
  std::printf("A::methodA() - B::MyStruct::Size == %d\n",
    g_global_instance_of_B.getMyStruct().Size);
}

void B::methodB() {
  mutex_guard lock(&B::g_mutex);
  MyStruct.Size = 1;
  std::printf("B::methodB() - B::MyStruct::Size == %d\n",
    g_global_instance_of_B.getMyStruct().Size);
}

extern "C" void* thread_1(void*) {
  g_global_instance_of_A.methodA();
  return NULL;
}

extern "C" void* thread_2(void*) {
  g_global_instance_of_B.methodB();
  return NULL;
}

int main() {
  pthread_t tid[2];
  pthread_create(&tid[0], NULL, thread_1, NULL);
  pthread_create(&tid[1], NULL, thread_2, NULL);
  for (int i = 0; i < 2; ++i) {
    pthread_join(tid[i], NULL);
  }
  return 0;
}

______________________________________________________________________

Okay, this program can run 3 ways... The first is that thread_1 runs first
and therefore misses the update. Second, thread_2 runs first and the update
is observed when thread_1 runs. The third is that they run together and race
through in which anything can happen. For instance, if thread_1 hits the
mutex first, then the update will not be observed.

If you want to ensure that thread_1 will ALWAYS see the mutation generated
by thread_2, well, you need someway to make sure that thread_2 runs first. A
simple and niave soultion is to use a simple semaphore. Think of this:

code listing 2 without a race-condition!
______________________________________________________________________
#include <cstdio>
#include <pthread.h>
#include <semaphore.h>

class mutex_guard {
  pthread_mutex_t* const m_mutex;

public:
  mutex_guard(pthread_mutex_t* const mutex)
   : m_mutex(mutex) {
    pthread_mutex_lock(m_mutex);
  }

  ~mutex_guard() {
    pthread_mutex_unlock(m_mutex);
  }
};

class A {
public:
  void methodA();
};

class B {
  friend class A;

  struct S {
    int Size;
    S() : Size() {}
  };

  S MyStruct;

  S& getMyStruct() {
    return MyStruct;
  }

  static pthread_mutex_t g_mutex;

public:
  void methodB();
};

pthread_mutex_t B::g_mutex = PTHREAD_MUTEX_INITIALIZER;

static B g_global_instance_of_B;
static A g_global_instance_of_A;

void A::methodA() {
  mutex_guard lock(&B::g_mutex);
  std::printf("A::methodA() - B::MyStruct::Size == %d\n",
    g_global_instance_of_B.getMyStruct().Size);
}

void B::methodB() {
  mutex_guard lock(&B::g_mutex);
  MyStruct.Size = 1;
  std::printf("B::methodB() - B::MyStruct::Size == %d\n",
    g_global_instance_of_B.getMyStruct().Size);
}

extern "C" void* thread_1(void* state) {
  sem_t* const sem = (sem_t*)state;
  sem_wait(sem);
  g_global_instance_of_A.methodA();
  return NULL;
}

extern "C" void* thread_2(void* state) {
  sem_t* const sem = (sem_t*)state;
  g_global_instance_of_B.methodB();
  sem_post(sem);
  return NULL;
}

int main() {
  pthread_t tid[2];
  sem_t sem;
  sem_init(&sem, 0, 0);
  pthread_create(&tid[0], NULL, thread_1, &sem);
  pthread_create(&tid[1], NULL, thread_2, &sem);
  for (int i = 0; i < 2; ++i) {
    pthread_join(tid[i], NULL);
  }
  sem_destroy(&sem);
  return 0;
}

______________________________________________________________________

Now, thread_1 will always see the mutation made by thread_2. Period, end of
story. thread_1 will ALWAYS output:

A::methodA() - B::MyStruct::Size == 1

Whats going on here? Why are the changes of Size by thread executing
methodB not visible to the thread executing methodA.
I thought that struct myStruct lies in the context of both
threads/methods.


Perhaps the thread in which methodA gets invoked happens to execute first,
thus it has no chance to observe the mutation made by the thread which
invokes methodB.

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