Re: Will Modern C++ Design ever get fixed? Organization: unknown

From:
Charles Bryant <n871108125.ch@chch.demon.co.uk>
Newsgroups:
comp.lang.c++.moderated
Date:
Wed, 20 Oct 2010 21:49:34 CST
Message-ID:
<2010-10-19-01-38.0@chch.demon.co.uk>
In article <ZZOdnY5hF_pwUjHRnZ2dnUVZ8uCdnZ2d@giganews.com>,
Leigh Johnston <leigh@i42.co.uk> wrote:
}My reply was slightly unclear, the following code snippet clarifies it I hope:
}
}static DWORD WINAPI thread_proc(LPVOID aThreadableObject)
}{
} ::Sleep(1000); // wait for a second
} bool* p = (bool*)aThreadableObject;
} if (p)
} *p = false;
} return 0;
}}
}
}int main()
}{
} bool gotOne = false;
} bool b = false; // not volatile
} HANDLE thread = ::CreateThread(NULL, 0, thread_proc, &b, 0, NULL);
} b = true;
} while(b)
} {
} gotOne = true;
} rand(); /* any (library) function which the optimizer cannot analyze seems to
}work,
} a wait on the thread or some mutex locking would be less contrived */
} }
} if (gotOne)
} std::cout << "volatile not needed";
}}

In case anyone is wondering, no compiler can optimise the test of b.
If the compiler does not know what ::CreateThread() does, then it must
allow for the possibility that it saves the address of b that was
passed in. If it does not know what rand() does, then it must allow
for the possibility that it uses the pointer saved by ::CreateThread()
to change b. Hence it cannot optimise away the repeated test of b.

Of course a compiler might be smart enough to know what those function
do, but in that case it would know that the address of b was likely to
be used by another thread and also could not optimise away the test of
b.

If a compiler was smart enough to know that rand() couldn't modify b
but not smart enough to know that ::CreateThread() created a thread,
which could modify b then it is an excellent example of the proverb that
"A little knowledge is a dangerous thing." because such a compiler is
useless for multithreaded code.

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