Re: Showing status of a long process

DDD <>
Fri, 21 Jan 2011 06:43:24 -0800 (PST)
wang ha escrito:

On 21 Jan., 04:35, DDD <> wrote:

There is one possible question. How do you arrange your "file

While(...) {




Is that so?

If so , the now phenomenon is right. Because the while loop will
occupy CPU until it out. And the main process
while (GetMessage(&msg, NULL, 0, 0))
                if (!TranslateAccelerator(msg.hwnd, hAc=

celTable, &msg))


can not dispatchMessage to WndProc function of the Dialog.

You can put your codes in a thread to achieve your destination.

Hi all gurus,
I've written a dialogue program in Visual C++ which processes many
files and might last long. I want to show the status of the process,
for example, "just processing the file abc.txt", on the GUI, where I
have put a static control with the variable m_strMsg for showing such
messages. During the processing the program changes m_strMsg if a new
file being processed is opened, and I haven't forgotten to write
"UpdateData(FALSE);" after changing m_strMsg. But the message on the
GUI does not change until the end of the program. What must be done t=


synchronize the GUI message and the process status? Or should I use
other architecture (for example, SDI) instead of dialogue program?
Many thanks in advance! Zitierten Text ausblenden -

- Zitierten Text anzeigen -

Yes, you are right. My code looks like:

while (there is file unprocessed) {
I've read in "VC++ in 21 Days" about Multitasking. 4 kinds of
multitasking are introduced there: critical sections, mutexes,
semaphores und events. What kind of multitasking should be used for my
purpose? Thanks!

A simple solution is

void ThreadFunction()

createThread(...ThreadFunction, ...);

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