Question about odd syntax: char* c = {"Text"};

From:
Bruce Adcock <bruce.adcock@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 26 May 2006 15:36:57 -0400
Message-ID:
<e57lcq$u57$1@news1.cse.ohio-state.edu>
Hi,

   I have run across the some strange syntax, to which I do not
understand the meaning:

     const char* xmlHeader = {"<?xml"};

(specifically, this can be found in "tinyxmlparse.cpp", Line 828, from
the "tinyxml" project on Sourceforge at
<http://sourceforge.net/projects/tinyxml/>). I should note that this
does compile with gcc v4.0.1.

   Originally, I thought this syntax would only make sense if we were
dealing with char*[] or char**. My second interpretation was that this
notation essentially dynamically allocates an array of chars,
initialized with "<?xml". However, this does not seem to hold, based on
the following test.

     #include <iostream>

     using namespace std;

     int main ()
     {
       const char* a = "Test 1 has address ";
       char* b = new char[12];
       const char* c = {"Test 3 has address "};
       char d[] = "Test 4 has address ";
       char e[12];

       cout << "a: " << a << ((const void *) a) << endl;
       cout << "b: Test 2 has address " << ((const void *) b) << endl;
       cout << "c: " << c << ((const void *) c) << endl;
       cout << "d: " << c << ((const void *) d) << endl;
       cout << "e: Test 5 has address " << ((const void *) e) << endl;

     // delete [] c;
     // delete c;
     }

In my particular instance, I get

     a: Test 1 has address 0x2eb0
     b: Test 2 has address 0x500150
     c: Test 3 has address 0x2ec4
     d: Test 3 has address 0xbfffed84
     e: Test 5 has address 0xbfffed98

This implies to me that the {}s do not actually do anything, as both a
and c do not appear to be pointing at something on the heap (like d and
e) or on the stack (like b). That can be further supported by
uncommenting either one of the delete's at the end, which gives me

     malloc: *** Deallocation of a pointer not malloced: 0x2ec4; This
     could be a double free(), or free() called with the middle of an
     allocated block; Try setting environment variable MallocHelp to see
     tools to help debug

My question is, does this notation actually serve any purpose? And while
I am at it, is there any nice notation to do in one statement what I
thought this did, i.e. something like

     char temp_literal[] = "<?xml";
     char* temp_pointer = new char[strlen (temp_literal)]";
     strcpy (temp_pointer, temp_literal);
     const char* c = temp_pointer;

             Thank you for any help,
             Bruce

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