Printing XML string With XML tags

"Joah Senegal" <>
Thu, 24 Apr 2008 00:24:35 +0200
Hello all,

I;m a beginner with XML. All I want is to print the XML string with tags. In
the following example, there is function called: xmlNodeGetString. This
function is getting a char* back. The result of this function is the XML
elements of the list without tags (Jaap, Kees, Kris). at the end of this
example a function xmlSaveFormatFile writes a XML file. looking like:

<?xml version="1.0"?>

So what I want to do is writing the lines normally writting in the file on
the screen using printf. So if I do a printf I need to get something like:

<?xml version="1.0"?>

I;ve searched for xmlfunctions for this, but I'm failing to find the right
one. Does anyone know how to get a output like above? I want do something
like this:

        char *fname ;
        for ( ; p ; p = p->next ) {
                 if (p->type == XML_ELEMENT_NODE) {
                        fname = (char *)SOMEXMLFUNCTION(.........) }
                        printf (fname);

In the place om SOMEXMLFUNCTION should me a xmlfunction that spits out
things like this:


#include <iostream>

#include <libxml/parser.h>

using namespace std ;

int main() {

        xmlNode *xNode ;
        xmlDocPtr doc ;

        doc = xmlNewDoc(BAD_CAST "1.0");

        xNode = xmlNewNode(NULL, BAD_CAST "LinkedList");
        xmlDocSetRootElement(doc, xNode);

        xmlNewChild(xNode,NULL,(xmlChar *)"Element", (xmlChar *)"Jaap" ) ;
        xmlNewChild(xNode,NULL,(xmlChar *)"Element", (xmlChar *)"Kees" ) ;
        xmlNewChild(xNode,NULL,(xmlChar *)"Element", (xmlChar *)"Kris" ) ;

        xmlNode * p = xNode->children ;

        char *fname ;
        for ( ; p ; p = p->next ) {
                 if (p->type == XML_ELEMENT_NODE) {
                        fname = (char *)xmlNodeListGetString(p->doc,
p->xmlChildrenNode, 1);

                cout << fname << endl ;

        xmlSaveFormatFile ("LinkedList.xml", doc, 0);


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