Re: acces of members of subclass

From:
Eric Sosman <Eric.Sosman@sun.com>
Newsgroups:
comp.lang.java.help
Date:
Mon, 28 Jul 2008 17:16:35 -0400
Message-ID:
<1217279702.726000@news1nwk>
Lew wrote:

Lew wrote:

The call to super() is *always* present. Any given class, in the
general case, can rely on the presence of super() call. Daniel and
you are not correct.


Eric Sosman <Eric.Sos...@sun.com> wrote:

     No, Mark is right, and Daniel and Lew are wrong.


I said that there was a call. I never claimed that it would always
succeed.


     You said "The call to super() is *always* present," but that is
not the case. It is absent in three cases: (1) the class happens to
be java.lang.Object, (2) there is an explicit call to a superclass
constructor other than super(), or (3) the superclass has no no-
arguments constructor. Case (1) need not concern us, but case (2)
is perfectly ordinary, and case (3) is code that cannot produce a
"given class" because it won't even compile.

     Lew (and the JLS) are right in saying that the compiler inserts a
call to super() if the constructor does not begin with a call to one


How can I be wrong if I said the same thing that the JLS does?


     I said you "are right," did I not?

of its superclass' constructors. But that does not guarantee that the
superclass actually *has* a no-arguments constructor that can be called
as plain super(). If it doesn't, there'll be a compile-time error.


I never said otherwise.

Try it!


The error that results proves that I was correct. There cannot be an
error on a call to super() unless there's a call to super() to have an
error.


     I suspect we may be in violent agreement, differing only in our
use of nomenclature. When you refer to a "given class," it seems you
mean a bunch of source code processed by javac, whether or not it can
be compiled. I take the word "class" to mean the thing loaded into
the JVM by a ClassLoader, so in my view an uncompilable source cannot
become a "class."

     You are right: The compiler will decorate constructors with calls
to super() in the absence of explicit calls to superclass constructors.

     I am right: Classes without calls to super() exist, and superclasses
exist that cannot be constructed via super() calls.

     Peace?

--
Eric.Sosman@sun.com

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