Re: Parsing Soap Response in java

On 4/4/2014 6:07 AM, emmna.90@gmail.com wrote:
 


 
 > some specific values of it .For example ,i need to have the value v1 o=

 
 > string parameter in operationname1 and v2 of string parameter of
 
 > operationname2.i tried with some tuto in the net but it doesn't work
 
 > for me.
 
 >
 


 

 


 


 


 


 


 


 


 

 


 

 

 


 

 

 


 

 


 


 


 

 


 


 


 


 


 


 
 
 
0) That is not the SOAP result as it is not well formed XML.
 
 
 
I will assume it looks like:
 
 
 
<?xml version='1.0' encoding='utf-8'?>
 
<soapenv:Envelope xmlns:soapenv="...">
 
     <soapenv:Body>
 
         <ns1:CommandResponseData xmlns:ns1="...">
 
             <ns1:CommandResult>
 
                 <ns1:TransactionResult>
 
                     <ns1:OperationResult>
 
                         <ns1:Operation name="operationname1"
 
modifier="modify1">
 
                             <ns1:ParameterList>
 
                                 <ns1:StringParameter
 
name="n1">v1</ns1:StringParameter>
 
                                 <ns1:DateTimeParameter
 
name="d1">value</ns1:DateTimeParameter>
 
                             </ns1:ParameterList>
 
                        </ns1:Operation>
 
                         <ns1:Operation name="operationname2"
 
modifier="modify2">
 
                             <ns1:ParameterList>
 
                                 <ns1:StringParameter
 
name="c1">v2</ns1:StringParameter>
 
                             </ns1:ParameterList>
 
                         </ns1:Operation>
 
                     </ns1:OperationResult>
 
                </ns1:TransactionResult>
 
            </ns1:CommandResult>
 
        </ns1:CommandResponseData>
 
    </soapenv:Body>
 
</soapenv:Envelope>
 
 
 
1) If you are process XML when you are doing SOAP then you are most
 
    like doing it wrong. You should be generating stub code from the
 
    WSDL and just make a method call and not worry about XML at all.
 
 
 
2) If you really need to parse the response manually, then I will
 
    recommend using XPath.
 
 
 
Example reading the above XML from a disk file soap.xml:
 
 
 
import java.io.FileReader;
 
import java.io.IOException;
 
 
 
import javax.xml.parsers.DocumentBuilder;
 
import javax.xml.parsers.DocumentBuilderFactory;
 
import javax.xml.parsers.ParserConfigurationException;
 
import javax.xml.xpath.XPath;
 
import javax.xml.xpath.XPathConstants;
 
import javax.xml.xpath.XPathExpressionException;
 
import javax.xml.xpath.XPathFactory;
 
 
 
import org.w3c.dom.Document;
 
import org.w3c.dom.Node;
 
import org.xml.sax.InputSource;
 
import org.xml.sax.SAXException;
 
 
 
public class ManualSoapParse {
 
    public static void main(String[] args) throws
 
ParserConfigurationException, SAXException, IOException,
 
XPathExpressionException {
 
         DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
 
         dbf.setNamespaceAware(false);
 
         DocumentBuilder db = dbf.newDocumentBuilder();
 
         Document doc = db.parse(new InputSource(new
 
FileReader("/work/soap.xml")));
 
         XPath xpath = XPathFactory.newInstance().newXPath();
 
         Node n1 =
 
(Node)xpath.evaluate("//Envelope/Body/CommandResponseData/CommandResult/T=

 
doc.getDocumentElement(), XPathConstants.NODE);
 
         System.out.println(n1.getNodeValue());
 
         Node c1 =
 
(Node)xpath.evaluate("//Envelope/Body/CommandResponseData/CommandResult/T=

 
doc.getDocumentElement(), XPathConstants.NODE);
 
         System.out.println(c1.getNodeValue());
 
     }
 
}
 
 
 
Note that I cheated and ignored namespaces. You can handle namespaces if
 
you need to or want to.
 
 
 
Arne