Re: Converting a string to an integer

"Jeff Higgins" <>
Sun, 25 Mar 2007 21:18:24 -0400
jt wrote:

import static java.lang.Integer.*;

public class WillThisWork {
  public static void main(String [] args) {
    String s = "023";
    String y = s.trim();
    Integer x = java.lang.Integer.decode(y);

      Integer x = decode(y);

    System.out.println("s as a string is " + s);
    System.out.println("y as a string is " + y);
    if (s.equals(y))
        System.out.println("They are the same");
        System.out.println("They are different");
System.out.println("Now see what x is " + x);

I know that this is probably a silly question, but if I import
java.lang.Integer.* why do I still have to fully qualify decode()? Is it
because it's a static method and MUST be fully qualified?
Note: I'm not far enough in the Java Tutorial to answer this question so
that's the only reason I'm asking you...

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