Re: Character.isDigit malfunction
<soup_or_power@yahoo.com> wrote in message
news:1170950008.920346.298190@q2g2000cwa.googlegroups.com...
On Feb 8, 10:40 am, Gordon Beaton <n...@for.email> wrote:
On 8 Feb 2007 07:22:40 -0800, soup_or_po...@yahoo.com wrote:
There is an error in your *real* code. My results don't agree with
yours, i.e. both posted examples work as advertised.
It would help if you posted an example of the string that gives the
strange result, and also indicated exactly where in the code you put
the call to getType(). In fact why not post a complete, compilable
example that exhibits the strange behaviour. Cut and paste!
The string is either an encrypted one or a number. I can't post the
encrypted ones. The number strings are like "012345". I put the
getType inside the for loop as follows:
[code snipped]
Here's a simplified version of your code (with all the file IO junk
removed), and a few extra debugging statements added. If you run it on your
strings, do you still get the same problem?
public class csv4 {
public static void main(String[] args) {
String ssn = "Manually type your string here";
boolean containsNonDigit = false;
for (int i = 0; i < ssn.length(); i++) {
System.err.println("i=" + i);
System.err.println("char=" + ssn.charAt(i));
System.err.println("chartype=" + Character.getType(ssn.charAt(i)));
System.err.println("isDigit=" + Character.isDigit(ssn.charAt(i)));
if (Character.isDigit(ssn.charAt(i))) {
continue;
}
containsNonDigit = true;
break;
}
System.out.println("containsNonDigit is " + containsNonDigit);
}
}
- Oliver