Re: Regex and Unicode

From:
"Oliver Wong" <owong@castortech.com>
Newsgroups:
comp.lang.java.programmer,comp.lang.java.help
Date:
Mon, 19 Mar 2007 12:41:04 -0400
Message-ID:
<yWzLh.46374$YK6.392096@wagner.videotron.net>
<michael.biden@gmail.com> wrote in message
news:1174321526.423436.288440@b75g2000hsg.googlegroups.com...

I have a situation in which I am receiving a String from a non-java
system. The system that generates the String attempts to encode some
characters such a slash to unicode. However it encodes characters
using the percent sign rathern than the backslash.

Thus the String test-victorf becomes test%u002dvictorf. I'd love to
be able to simply replace the percent with a backslash, but it seems
that there is no way to dynamically insert the backslash like a
literal. For example:
public static void main (String args[]){
String user = "test%u002dvictof";
user = user.replace('%', '\\');
System.out.println(user);
                }

Does not work. The output is test\002dvictorf.

So I tried to use a regular expression with a capturing parantheses:
public static void main (String args[]){
String user = "test%u002dvictof";
user = user.replaceAll("%u([a-f | A-F | 0-9][a-f | A-F | 0-9][a-f |
A-F | 0-9][a-f | A-F | 0-9])",
Character.toString((char)Integer.valueOf("$1", 16).intValue()) );
System.out.println(user);
                }
Which generates a java.lang.NumberFormatException becuase the compiler
does not like the $1 at runtime. It seems that the $1 is being
interpretted literally. The real value of $1 at run time is '002d'


    "$1" is interpreted literally, because "$1" is a literal. It has the
same value at runtime as it does a compile time, namely the two-character
string consisting of the character '$' followed by the character '1'.

    Do the replace in three smaller steps instead of one big step: In the
first step, extract the "specially-encoded" char, "%u002d", and in the
second step, convert this 6-character string into a 1-character string
"-". In the third step, put your 1-character string where it should be in
the original string you were parsing.

    - Oliver

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