Re: Read binary data file

From:
Lew <lew@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Fri, 31 Aug 2007 07:21:59 -0400
Message-ID:
<z7ednX8bL5xKZErbnZ2dnUVZ_tajnZ2d@comcast.com>
Charles wrote:

Let's review what the OP stated

A struct is given in C++

Data needs to read from a file in Java.

You have the following data types

unsigned long
unsigned short

As previously stated by other posters the Endianness of the operating
system should affect how the output file is encoded. I assume this to
be true but have not verified it to be true.

We assume all unsigned longs and unsigned short will ALWAYS have the
same bytesize.

The complete struct is given as

unsigned long data1;
unsigned short data2;
unsigned short data3;
unsigned long data4;

Can we also assume that the data will always be sequenced as described
in the STRUCT?
I don't see any argument why the data will be out of sequence as
defined in the STRUCT.


But we do not know the padding, and the OP doesn't know what those sizes are,
nor the endianness of their files. They don't even know in what format the
floating-point values are stored: IEEE? We need all that information to craft
a Java equivalent, and we don't have it. The OP doesn't have it, by their
account.

Does the input file get modified when it is transported from one
operating system to another?
I assume NO. This is not verified.


But if endianness and padding matter, the fact that it is not modified will
make it unreadable on the second system.

Are there equivalents of unsigned long and unsigned short in Java?


No.

Are they the same byte size?


We do not know. The OP hasn't given us enough information.

Do they encode the data the same?


We do not know. The OP hasn't given us enough information.

Try to read in Java and verify with known data. If you don't know any
of the data values this becomes a harder task.


It's already impossible based on the information given. How much harder can
it get?

--
Lew

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