Re: regex bug jre6???

From:

"hiwa" <HGA03630@nifty.ne.jp>

Newsgroups:

comp.lang.java.programmer

Date:

12 Dec 2006 01:11:57 -0800

Message-ID:

<1165914717.402210.6710@16g2000cwy.googlegroups.com>

triVinci@gmail.com wrote:

Hello all and TIA for any and all insight...

My application reads in a regex pattern as a string from an external
source.
When the pattern contains an escaped backslash ("\\"), my existing code
works great under 1.4.2 and 1.5.

I'm simply calling...

string.matches(regex);

In jre6, the same code, processing the same regex, throws a
PatternSyntaxException complaining that "\\" is an Illegal/unexpected
escape sequence.

Is this a bug in jre6? Are there any suggestions on how to work-around
this issue?

-tv

1.6 works normally. Here's a SSCCE.
----------------------------------------------------------------------
/** content of regex.txt **
\\[newline]
***************************/
import java.io.*;
import java.util.regex.*;

public class RegX{

  public static void main(String[] args){
    String regex = null;
    String text = "abc\\efg\\xyz\\";

    try{
      BufferedReader br
        = new BufferedReader(new FileReader("regex.txt"));
      regex = br.readLine();
    }
    catch (Exception e){
      e.printStackTrace();
    }

    Pattern pat = Pattern.compile(regex);
    Matcher mat = pat.matcher(text);

    while (mat.find()){
      System.out.println(mat.group());
    }
  }
}
--------------------------------------------------------------------------------------