Re: exception

From:

"Art Cummings" <aikiart7@gmail.com>

Newsgroups:

comp.lang.java.help

Date:

Thu, 29 Nov 2007 23:19:13 -0500

Message-ID:

<tOGdnRv66-VEE9LanZ2dnUVZ_vKunZ2d@comcast.com>

My apologies, the code for the throw was assumed. I've included it here.

Thanks

public void actionPerformed(ActionEvent e)
{
try
{

addingStudent();
}
catch (IOException x)

{
String name;
name = StudentTextField.getText();
FileWriter swriter = new FileWriter("c:\\studname.txt",true);
FileWriter gwriter = new FileWriter("c:\\grades.txt",true);
PrintWriter outputFile2 = new PrintWriter(gwriter);
PrintWriter outputFile= new PrintWriter(swriter);
outputFile.println(name);
outputFile2.println("0,0,0");
outputFile.close();
outputFile2.close();
StudentTextField.setText("");

}

"Eric Sosman" <esosman@ieee-dot-org.invalid> wrote in message
news:KrKdney7gd1EGNLanZ2dnUVZ_hisnZ2d@comcast.com...

Art Cummings wrote:

[...]
The error message I get.
X?StudentAddWindow.java:92: exception java.io.IOException is never
thrown in body of corresponding try statement

private class addButtonListener implements ActionListener
{

public void actionPerformed(ActionEvent e)

{

try
{ String name;
} catch (IOException x)
[...]

Well, okay, why do you thing `String name;' is going
to throw an IOException? The whole inside of the try block
does nothing at all -- it declares a variable `name' that
can refer to String objects, but never uses it and never
does anything -- so there's no way an IOException can ever
be thrown. Why are you trying to catch something that
cannot exist?

--
Eric Sosman
esosman@ieee-dot-org.invalid