Re: method parameters
david wrote:
So, what I should do to make this work?
I want to send pointer, allocate something (matrix) there, change
value and after that in main code I still want to have the data. In
other languages I would send pointer, pointer to pointer or reference.
There are ways of emulating a pointer to pointer, by passing a reference
to an object that has a reference field. However, the resulting code
would be very awkward and not at all idiomatic.
You don't say why the method returns boolean, rather than an array
reference, and I have no idea what "Kazkas blogai ir tiek" means, but I
guess from the code that you are using the return to indicate success or
failure:
if (!fLoadData(linksVault, args[0])) {
System.out.println("Kazkas blogai ir tiek");
System.exit(1);
}
In Java, it is more usual to return the thing you are trying to return,
and use exceptions to indicate the nature and reason for any failure to
return it.
The quoted code would turn into:
try{
linksVault = fLoadData(args[0]);
}catch(SomeException e){
System.out.println("Kazkas blogai ir tiek");
System.exit(1);
}
Replace "SomeException" with an appropriate exception class. For
example, if the only way fLoadData can fail is an I/O failure, it might
be appropriate to just pass through IOException.
More generally, you seem to be an experienced programmer in at least one
other language, but you are new to Java. I strongly recommend working
through a basic book or tutorial on Java. Despite superficial
similarities to e.g. C++, you will find it very hard to code in Java by
translating C++ idioms. It is much better to learn Java idioms.
Patricia