Re: catching exceptions in subclass' constructor?

(in these examples my Exceptions are chosen arbitrarily
from those in java.lang)

Consider a class 'A'

class A {
     public A(int i) throws NoSuchFieldException {
     };

};

It (for reasons all its own) can throw an exception.

Now consider a sub-class 'B', that extends 'A'.

I would like to give it 2 constructors, one a simple
"clone" of the 'A' constructor, and a parameterless
constructor. I want this because in my real
app 'B' has many subclasses.

If a parameterless constructor that throws
no exceptions can be managed, I won't need to declare
a constructor at all in the (many) sub classes,
which will be helpful to me.

The first constructor is trivial.

class B extends A {
     public B(int i) throws NoSuchFieldException {
         super(i);
     };

}

Now, since I am going to (carefully) provide
a valid default argument in the B() constructor,
I do not want it to throw a checked exception,
so I map" it to a runtime exception.

So I tried:

    public B() {
         try {
             this(10);
         } catch(NoSuchFieldException e) {
             throw new IllegalStateException(e);
         }
     }

but the compiler says:

" call to this must be first statement in constructor"

I would welcome advice on how to achieve my goal (a parameterless
constructor for B that does not throw an exception).