Re: SAX and DOM query

From:

"Mike Schilling" <mscottschilling@hotmail.com>

Newsgroups:

comp.lang.java.programmer

Date:

Tue, 28 Nov 2006 06:55:39 GMT

Message-ID:

<L3Rah.5135$wc5.189@newssvr25.news.prodigy.net>

"gk" <srcjnu@gmail.com> wrote in message
news:1164657760.644337.31050@l12g2000cwl.googlegroups.com...

import org.apache.xerces.parsers.DOMParser;
import org.xml.sax.SAXException;
import org.w3c.dom.Document;
import java.io.IOException;

public class DOMExample{

   public static void main(String args[]) throws IOException,
SAXException{

       DOMParser parser = new DOMParser();
       parser.parse("games.xml");

       Document dom = parser.getDocument();
   }

}

In the body of the main method, you have the code that creates a new
instance of the DOMParser class and assigns it to the variable named
parser. The second line calls the parse method of the DOMParser class
and passes in the name of the XML file you have created.

The parse method throws two exceptions: java.io.IOException and
org.xml.sax.SAXException. Rather than wrap the call to the parse method
in a try/catch, main throws these two exceptions.

Question:
----------------

its very surprising to me that there is no DOMException! ,.....look,
we are studying here DOM implementation .... its the DOM chapter
then why SAXException came ?

Bad naming conventions. There is a class DOMException, but t's thrown when
manipulating a DOM illegally, e.g.

Element elm;
elm.appendChild(elm);

Parsing an XML file can't result in that sort of error, so DOMException
won't be thrown. Both DOM and SAX parsers throw the same sort of exceptions
when parsing XML, and they should probably be called XMLParserException
instead of SAXException.