Re: Reading Binary File Values

From:
Eric Sosman <Eric.Sosman@sun.com>
Newsgroups:
comp.lang.java.help
Date:
Thu, 15 Oct 2009 15:44:13 -0400
Message-ID:
<1255635853.621864@news1nwk>
garyinri@yahoo.com wrote:

On Oct 15, 1:07 pm, Eric Sosman <Eric.Sos...@sun.com> wrote:

garyi...@yahoo.com wrote:

Hello.
I have a file that was transferred from a mainframe environment. Due
to the way that this mainframe data is stored, the file was
transferred to a PC as binary data.

                            ^^^^^^^^^^^

[...]


I found the following piece of code online that does exactly what I
want, but it expects the input to be a string variable. If I could
get the individual bytes properly into a string, I could use the
following logic:

import java.io.*;
import java.lang.*;

public class HexaToChar{
    public static void main(String[] args) throws IOException{
        BufferedReader bf = new BufferedReader(new InputStreamReader
(System.in));
        System.out.println("Enter the hexa number:");
        String str= bf.readLine();
        int i= Integer.parseInt(str,16);
        System.out.println("Decimal:="+ i);
    }
}


     This code does *not* do what you want -- at any rate, it does
not do what you say you want. You asked about reading a file where
two bytes with the values D3 4A represent the number 54090 (this
was one of the examples in your original post). The code you found
would be suitable for a file in which the four *characters* (not
necessarily "bytes") 'D' '3' '4' 'A' represent that number. That's
a different matter entirely.

--
Eric.Sosman@sun.com

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