Re: java - php

From:

"Oliver Wong" <owong@castortech.com>

Newsgroups:

comp.lang.java.help

Date:

Fri, 07 Jul 2006 14:33:17 GMT

Message-ID:

<Ngurg.133533$771.50112@edtnps89>

<allanallansson@spray.se> wrote in message
news:1152247213.895409.296870@p79g2000cwp.googlegroups.com...

Oliver Wong wrote:

<allanallansson@spray.se> wrote in message
news:1152181891.972424.318880@q16g2000cwq.googlegroups.com...

Hi i want to send a file to php (with post) and i also want to set a
variable in the same form. example ("&myvar=" + myvar).

You can send arbitrary data via a POST request. It's also possible to
send data via both POST and GET simultaneously. Simply POST to a GET url.
E.g. POST to http://foo.com/bar?getVariable=value

- Oliver

If you could explain that with a code snippet i would be most pleased!

Thank you in advance, Allan

Take your original code, and change the beginning from:

<oldCode>
public void postFile(String exsistingFileName) {
try {
    FileInputStream fileInputStream = new FileInputStream( new
   File(exsistingFileName) );

    // Open a HTTP connection to the URL
    System.out.println("Connecting to server...");

    conn = (HttpsURLConnection) (new URL(urlString)).openConnection();
</oldCode>

to

<newCode>
public void postFile(String exsistingFileName) {
try {
    FileInputStream fileInputStream = new FileInputStream( new
   File(exsistingFileName) );

    // Open a HTTP connection to the URL
    System.out.println("Connecting to server...");

    conn = (HttpsURLConnection) (new URL(urlString +
"?myVar="+myVar+"&myVar2="+myVar2)).openConnection();
</newCode>

    This assumes that urlString didn't contain a question mark already.

    - Oliver